C Expressions (Arithmetic and Logical Operator) Interview Questions Quiz.

Right Answer.

Explanation:

In expression if (a == 10 && a++ == 11)

a == 10 is true.

a++ means post-increment.

a++ == 11, here a == 11 is compared first and then a++ executes.

So first, a == 11 comparison happens, and then 'a' increments to 11.

So, when a++ == 11 executes, 'a' value is 10. So, a++ == 11 is false.

And result is true && false = false, thus o/p is FALSE: 11

Right Answer.

1) Initially, a=2,b=4,c=3,d=0,x = garbage,y = garbage;

2) x= (a=0) && (b=7);

a = 0 means '0' assigned to 'a' and it is false. As a = 0 gives false, b = 7 will not be executed. Because for logical AND operation, if the first condition is "false" then the result will be "false" always.

x= (a=0) && (b=7) = false = 0

Now, a=0,b=4,c=3,d=0,x = 0,y = garbage.

3)  y=(c=5) || (d=0);

c = 5, '5' is assigned to 'c' and the condition will be true. d = 0, '0' is assigned to 'd', and condition will be false.

y=(c=5) || (d=0) = true || false =. true = 1;

Now, a=0,b=4,c=5,d=0,x = 0,y = 1.

First, printf o/p will be: a=0,b=4,c=5,d=0,x=0,y=1

4) x=(a==0) && (b=10) = true && true = true = 1

Now, a=0,b=10,c=5,d=0,x=1,y=1

5)  y=(c==6) || (d=5) = false || true = true = 1

Now, a=0,b=10,c=5,d=5,x=1,y=1

For the second printf o/p will be: a=0,b=10,c=5,d=5,x=1,y=1

Right Answer!

ch = 'A' = 65 in ascii

var = ch + 4 = 65 + 4 = 69

%d of ch is 65

%c of ch is 'A'

%d of var is 69 which is ascii of 'E'

%c of var is character 'E'

Right answer!

Incrementing and decrementing are only allowed on variables. Not on the literal value directly.

Right Answer!

Explanation:

c = a > b = 5 > 10 = false = 0

d = (a < b) && (c < a) = (5 < 10) && (0 < 5) = (true) && (true) = true = 1

Right Answer.

Explanation:

x == 5 is true

for logical OR, when any condition is calculated as true then further conditions will not be verified.

So, ++y will not be executed at all.

So, z = true = 1, x = 5 and y = 5.

Right Answer.

f == 2.4, f is float but value 2.4 is by default double.

So f == 2.4 = false as the value of 2.4 in float and double are not the same with precision.

if, 2.4 is typecased with float then "f == float(2.4)" will be true.

Right Answer!

Explanation:

c = i = f:

'f' value is 67.222.

i = f, implicit typecasting is done by the compiler, float value '67.222' is demoted to int value '67'.

c = i, 'c' is also assigned with value '67'.

%.3f of 'f' = 67.222(float values up to precision of 3)

%i of 'i' = 67

%c of 'c' = 'C' (67 is the ascii code of character 'C')